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245=6x^2
We move all terms to the left:
245-(6x^2)=0
a = -6; b = 0; c = +245;
Δ = b2-4ac
Δ = 02-4·(-6)·245
Δ = 5880
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{5880}=\sqrt{196*30}=\sqrt{196}*\sqrt{30}=14\sqrt{30}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-14\sqrt{30}}{2*-6}=\frac{0-14\sqrt{30}}{-12} =-\frac{14\sqrt{30}}{-12} =-\frac{7\sqrt{30}}{-6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+14\sqrt{30}}{2*-6}=\frac{0+14\sqrt{30}}{-12} =\frac{14\sqrt{30}}{-12} =\frac{7\sqrt{30}}{-6} $
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